Become a supporter to remove this ad

User Tag List

+ Reply to Thread
Results 1 to 7 of 7

Thread: engineering question

  1. #1
    Member Kaido's Avatar
    Join Date
    Dec 2007
    Location
    Perth
    Liked
    9 times
    Posts
    1,965
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)

    engineering question

    Hey,

    Just wondering if anyone would be able to help me out im trying to work out Hoop strain for on my labs for uni.

    and i can't seems to find the method of working it out

    I know that normal strain E = elongation/original length

    but my question is relating to a thin wall cylinder with open ends and mohr's circle



    any help would be great
    Last edited by Kaido; 31-03-2009 at 04:44 PM.

  2. #2
    Member
    Join Date
    Jul 2008
    Location
    Mundaring
    Motorbike
    Suzuki DR650 commuter, BMW K100RS trackie
    Liked
    0 times
    Posts
    884
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    Surely hoop strain in a thin walled cylinder is basically just tensile strain in the wall. That is, the circumference will increase in accordance with E, and so the diameter, being proportional to circumference, will also increase in accordance with E.

    It's a long time since I did this stuff formally, but that's how I remember thinking of it.

    Of course, Mohr's circle implies that torsion comes into this somewhere, at which point, I'm afraid, I'm buggered.

  3. #3
    Member Kaido's Avatar
    Join Date
    Dec 2007
    Location
    Perth
    Liked
    9 times
    Posts
    1,965
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    Quote Originally Posted by PatB View Post
    Surely hoop strain in a thin walled cylinder is basically just tensile strain in the wall. That is, the circumference will increase in accordance with E, and so the diameter, being proportional to circumference, will also increase in accordance with E.

    It's a long time since I did this stuff formally, but that's how I remember thinking of it.

    Of course, Mohr's circle implies that torsion comes into this somewhere, at which point, I'm afraid, I'm buggered.
    thanks for that Patb, i was thinking along the similar lines.

    I have reading from 6 strain gauges,

    and in my notes it mention i should plot hoop stresses v's hoop strains work out the gradient and that will be an est of E.

    However im confused as i have a equation for hoop stress. and im not sure if i just take the reading from gauge 1 (y direction) as the hoop strain.

    For some reason i have written down Hoop Strain = stress x E however the whole point of the exerices is to work out E from the experimental data (strain gauge readings)
    Last edited by Kaido; 31-03-2009 at 05:12 PM.

  4. #4
    Member Argon's Avatar
    Join Date
    Jan 2009
    Location
    Tuart Hill, Perth
    Motorbike
    2006 - Ninja 636
    Liked
    0 times
    Posts
    744
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    ha ha, I got that lab report somewhere if you want it

    Is that with Kian Teh?

  5. #5
    Member
    Join Date
    Jul 2008
    Location
    Mundaring
    Motorbike
    Suzuki DR650 commuter, BMW K100RS trackie
    Liked
    0 times
    Posts
    884
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    OK, I'm assuming the experimental setup to be a cylindrical pressure vessel, in which you vary the applied pressure and read strain from the strain gauges.

    If that's so, being an Occam's Razor kind of chap, I can't see any reason to need the readings from any of the SGs apart from the one measuring circumferentially.

    Stress is easy to work out, based on the pressure in the vessel, the longitudinal cross sectional area and the vessel length and wall thickness (hmm...if you haven't got a wall thickness, that complicates matters). Since E=Stress/Strain, it's then a simple matter to find E. Or, doing it graphically, if you plot stress up the y axis and strain along the x axis, the gradient of the graph will represent E.

  6. #6
    Member Kaido's Avatar
    Join Date
    Dec 2007
    Location
    Perth
    Liked
    9 times
    Posts
    1,965
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    Quote Originally Posted by Argon View Post
    ha ha, I got that lab report somewhere if you want it

    Is that with Kian Teh?
    LOL yes it is =p

    i'm just finishing up my conclusion now but wouldn't mind a look-see to see if i got everything right

    Quote Originally Posted by PatB View Post
    OK, I'm assuming the experimental setup to be a cylindrical pressure vessel, in which you vary the applied pressure and read strain from the strain gauges.

    If that's so, being an Occam's Razor kind of chap, I can't see any reason to need the readings from any of the SGs apart from the one measuring circumferentially.

    Stress is easy to work out, based on the pressure in the vessel, the longitudinal cross sectional area and the vessel length and wall thickness (hmm...if you haven't got a wall thickness, that complicates matters). Since E=Stress/Strain, it's then a simple matter to find E. Or, doing it graphically, if you plot stress up the y axis and strain along the x axis, the gradient of the graph will represent E.
    yeah i ended up confusing myself by some equations i wrote down that weren't needed. i just ended up plotting strees v's strain and found the gradient, which work out correct in the end.

  7. #7
    Member zed7fiddy's Avatar
    Join Date
    Jan 2008
    Location
    NSW
    Motorbike
    A Beast
    Liked
    0 times
    Posts
    1,004
    Mentioned
    0 Post(s)
    Tagged
    0 Thread(s)
    ahh I remember that lab lol... if you still need a hand PM me.
    '82 TS 185 - '89 CD250U - '94 ZZR 250 - '06 Z750 & '79 DS80

    Muscle Bikes Rock. You heard me. And go minibikes! Wheeeeeeeeeee

+ Reply to Thread

Bookmarks

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts

Content Relevant URLs by vBSEO 3.6.0